TOP 10 MIXTURE ALLEGATIONS AND QUESTIONS FOR SBI PO 2019
Quantitative Aptitude plays a crucial role in Banking Exams. TOP 10 Mixtures and Alligations questions for sbi po 2019 and other banking exams, ibps.
in this article we are providing top 10 mixture and allegations questions for practice more and more is the only way to improve accuracy as well as speed(because of the sectional timing allocated for every section).
TOP TEN QUANTITATIVE APTITUDE QUESTIONS
MIXTURE ALLEGATIONS
1. A Container contains 192 liters of Milk. A seller draws out x% of Milk and replaced it with the same quantity of water. He repeated the same process for 3 times. And thus Milk content in the mixture is only 81 liter. Then how much percent he withdraw every time?
1. 10%
2. 15%
3. 18%
4. 20%
5. 25%
2. A Jar contains 30 liters mixture of Milk and Water in the ratio of x:y respectively. When 10 liter of the mixture is taken out and replaced it water, then the ratio becomes 2:3. Then what is the initial quantity of Milk in the Jar?
1. 12 Liter
2. 15 Liter
3. 18 Liter
4. 20 Liter
5. None
3. A Container contains ‘X’ Liters of Milk. A thief stole 50 Liters of Milk and replaced it with the same quantity of water. He repeated the same process further two times. And thus Milk in the container is only ‘X-122’ liters. Then what is the quantity of water in the final mixture?
1. 122 Liter
2. 124 Liter
3. 128 Liter
4. 250 Liter
5. Cannot be determined
4. A Jar contains 100 liters of Milk a thief stole 10 liters of Milk and replaced it with water. Next, he stole 20 liters of Milk and replaced it with water. Again he stole 25 liters of Milk and replaced with water. Then what is the quantity of water in the final mixture?
1. 55 Liter
2. 54 Liter
3. 50 Liter
4. 46 Liter
5. None
5. In a 250 liter of a mixture of Milk and Water, Water is X%. The milkman sold 50 liters of the mixture and replaced same quantity with water. If the percent of Milk in final mixture is 64%, then what is the percentage of Milk in the initial mixture?
1. 20%
2. 40%
3. 50%
4. 60%
5. 80%
6. A jar contains ‘x’ liters of Milk, a seller withdraws 25 liter of it and sells it at Rs.20 per liter. He then replaces it water. He repeated the process total three times. Every time while selling he reduces selling price by Rs.2. After this process Milk left in the mixture is only 108 liters so he decided to sell the entire Mixture at Rs. 15 per liter. Then how much profit did he earned if bought Milk at Rs.20 per liter?
1. Rs.50
2. Rs.70
3. Rs.90
4. Rs.100
5. None
7. ‘X’ Liters of the mixture contains Milk and Water in the ratio 4:3. If 13 liters of Water is added then the ratio becomes 1:1. Then what is the final quantity of water in the mixture?
1. 39
2. 52
3. 56
4. 72
5. Cannot be determined
8. A Jar contains 200 liters of Milk a thief stole ‘X’ liters of Milk and replaced it with water. Next, he stole 40 liters of Milk and replaced it with water. Again he stole 50 liters of Milk and replaced with water. If the quantity of water in the final mixture is 92 liters. Then what is the value of X?
1. 10 Liter
2. 15 Liter
3. 20 Liter
4. 30 Liter
5. 50 Liter
9. From a container, a thief has stolen 10 liters of Milk and replaced with the same quantity of water. He repeated the process for three times, then the ratio of Milk to water became 343:169.The initial amount of Milk in the container is?
1. 80 liter
2. 100 liter
3. 120 liter
4. 130 liter
5. None
10. A Jar contains a mixture of Milk and Water 18 and 12 Liters respectively. When ‘x’ liter of the mixture is taken out and replaced with the same quantity of Water, then the ratio of Milk and Water becomes 2:3. Then what is the quantity of Water in final Mixture?
1. 12 Liter
2. 15 Liter
3. 18 Liter
4. 20 Liter
5. None
ANSWERS WITH EXPLANATION
1Q: Answer – 5. 25%
Explanation :
81 = 192(1-x/100)³
x = 25
2Q: Answer – 3. 18 Liter
Explanation :
x+y =30
(x-10*x/x+y)/ (y-10*y/(x+y) + 10) = 2/3
2x-4/3y = 20
x =18
3Q: Answer –1. 122 Liter
Explanation :
X-122 = X(1-50/X)³
X = 250 Liter
Milk = 250-122 = 128
Water = 122
4Q:Answer – 4. 46 Liter
Explanation :
Solution:
Milk = 100*90/100*80/100*75/100 = 54
Water = 100-54 = 46
5Q: Answer – 5. 80%
Explanation :
Milk = 250*(100-x/100)
50 liters replaced then
250*(100-x/100) – 50*(100-x/100) = 64% of 250
X = 20%
Milk = 80%
6Q: Answer – 2. Rs.70
Explanation :
Seller sells Milk at Rs.20,18 and 16 respectively for three times
= 25*(20+18+16) = 1350
108 = x(1-25/100) 3
x =256 liter
He sold entire 256 at Rs.15 =256*15 = 3840
Cost price = 256*20 = 5120
profit = 5190-5120 = 70
7Q: Answer – 2. 52
Explanation :
4x/3x+13 = 1
x = 13
Water = 3x+13 = 39+13 = 52
8Q: Answer –3. 20 Liter
Explanation :
Milk = 200-92 =108
108 = 200*(200-x)/200*160/200*150/200
x = 20 Liter
9Q: Answer – 1. 80 liter
343x = 512x(1-10/y)
y = 80
10Q: Answer – 3. 18 Liter
Explanation :
(18-x*18/30)/(12- x*12/30+x) =2/3
x = 10
Water = 12+3/5*10 = 18
for more questions about Quantitative Aptitude go to
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1. A Container contains 192 liters of Milk. A seller draws out x% of Milk and replaced it with the same quantity of water. He repeated the same process for 3 times. And thus Milk content in the mixture is only 81 liter. Then how much percent he withdraw every time?
1. 10%
2. 15%
3. 18%
4. 20%
5. 25%
2. A Jar contains 30 liters mixture of Milk and Water in the ratio of x:y respectively. When 10 liter of the mixture is taken out and replaced it water, then the ratio becomes 2:3. Then what is the initial quantity of Milk in the Jar?
1. 12 Liter
2. 15 Liter
3. 18 Liter
4. 20 Liter
5. None
3. A Container contains ‘X’ Liters of Milk. A thief stole 50 Liters of Milk and replaced it with the same quantity of water. He repeated the same process further two times. And thus Milk in the container is only ‘X-122’ liters. Then what is the quantity of water in the final mixture?
1. 122 Liter
2. 124 Liter
3. 128 Liter
4. 250 Liter
5. Cannot be determined
4. A Jar contains 100 liters of Milk a thief stole 10 liters of Milk and replaced it with water. Next, he stole 20 liters of Milk and replaced it with water. Again he stole 25 liters of Milk and replaced with water. Then what is the quantity of water in the final mixture?
1. 55 Liter
2. 54 Liter
3. 50 Liter
4. 46 Liter
5. None
5. In a 250 liter of a mixture of Milk and Water, Water is X%. The milkman sold 50 liters of the mixture and replaced same quantity with water. If the percent of Milk in final mixture is 64%, then what is the percentage of Milk in the initial mixture?
1. 20%
2. 40%
3. 50%
4. 60%
5. 80%
6. A jar contains ‘x’ liters of Milk, a seller withdraws 25 liter of it and sells it at Rs.20 per liter. He then replaces it water. He repeated the process total three times. Every time while selling he reduces selling price by Rs.2. After this process Milk left in the mixture is only 108 liters so he decided to sell the entire Mixture at Rs. 15 per liter. Then how much profit did he earned if bought Milk at Rs.20 per liter?
1. Rs.50
2. Rs.70
3. Rs.90
4. Rs.100
5. None
7. ‘X’ Liters of the mixture contains Milk and Water in the ratio 4:3. If 13 liters of Water is added then the ratio becomes 1:1. Then what is the final quantity of water in the mixture?
1. 39
2. 52
3. 56
4. 72
5. Cannot be determined
8. A Jar contains 200 liters of Milk a thief stole ‘X’ liters of Milk and replaced it with water. Next, he stole 40 liters of Milk and replaced it with water. Again he stole 50 liters of Milk and replaced with water. If the quantity of water in the final mixture is 92 liters. Then what is the value of X?
1. 10 Liter
2. 15 Liter
3. 20 Liter
4. 30 Liter
5. 50 Liter
9. From a container, a thief has stolen 10 liters of Milk and replaced with the same quantity of water. He repeated the process for three times, then the ratio of Milk to water became 343:169.The initial amount of Milk in the container is?
1. 80 liter
2. 100 liter
3. 120 liter
4. 130 liter
5. None
10. A Jar contains a mixture of Milk and Water 18 and 12 Liters respectively. When ‘x’ liter of the mixture is taken out and replaced with the same quantity of Water, then the ratio of Milk and Water becomes 2:3. Then what is the quantity of Water in final Mixture?
1. 12 Liter
2. 15 Liter
3. 18 Liter
4. 20 Liter
5. None
ANSWERS WITH EXPLANATION
1Q: Answer – 5. 25%
Explanation :
81 = 192(1-x/100)³
x = 25
2Q: Answer – 3. 18 Liter
Explanation :
x+y =30
(x-10*x/x+y)/ (y-10*y/(x+y) + 10) = 2/3
2x-4/3y = 20
x =18
3Q: Answer –1. 122 Liter
Explanation :
X-122 = X(1-50/X)³
X = 250 Liter
Milk = 250-122 = 128
Water = 122
4Q:Answer – 4. 46 Liter
Explanation :
Solution:
Milk = 100*90/100*80/100*75/100 = 54
Water = 100-54 = 46
5Q: Answer – 5. 80%
Explanation :
Milk = 250*(100-x/100)
50 liters replaced then
250*(100-x/100) – 50*(100-x/100) = 64% of 250
X = 20%
Milk = 80%
6Q: Answer – 2. Rs.70
Explanation :
Seller sells Milk at Rs.20,18 and 16 respectively for three times
= 25*(20+18+16) = 1350
108 = x(1-25/100) 3
x =256 liter
He sold entire 256 at Rs.15 =256*15 = 3840
Cost price = 256*20 = 5120
profit = 5190-5120 = 70
7Q: Answer – 2. 52
Explanation :
4x/3x+13 = 1
x = 13
Water = 3x+13 = 39+13 = 52
8Q: Answer –3. 20 Liter
Explanation :
Milk = 200-92 =108
108 = 200*(200-x)/200*160/200*150/200
x = 20 Liter
9Q: Answer – 1. 80 liter
343x = 512x(1-10/y)
y = 80
10Q: Answer – 3. 18 Liter
Explanation :
(18-x*18/30)/(12- x*12/30+x) =2/3
x = 10
Water = 12+3/5*10 = 18
for more questions about Quantitative Aptitude go to
for answers click here entire questions pdf file
for more study material visit homepage

Very nice and helpful.
ReplyDeleteBut, I want to know about the solution of no.6 math.
In the 4th line of the explanation how does 100 come? Because there has been said nothing about any percentage. There has been said in the question: 25 liter not 25percent.
Pls,help.